What is the equation of a circle with a center at (-4,0) that passes through the point (-2,1)

Hello from MrBillDoesMath! Answer: The third choice, (x+4)^2  + y^2 = 5 Discussion: Since the center is (-4.0) the equation of the circle with radius "r" is:(x - (-4))^2 + ( y - 0)^2 = r^2       => as -(-4) = 4(x+4)^2 + y^2 = r^2         Look at the choices provided. Only the third choice is of this form so the answer is(x+4)^2  + y^2 = 5            (*)Note this circle passes through (-2,1) as(-2 + 4)^2 + (1)^2 =(-2)^2 + 1^2 =4 + 1 = 5which agrees with (*) Thank you, MrB