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What are the excluded values of x for x+4/ -3^2+12x+36
4 months ago
Q:
What are the excluded values of x for x+4/ -3^2+12x+36
Accepted Solution
A:
x+4 / -3x^2 + 12x + 36
= x + 4 / -3 ( x^2 - 4x - 12)
= x - 4 / -3(x - 6)(x + 2)
the excluded values make the denominator = 0
so they are 6 and -2 Answer